A theater is presenting a program on drinking and driving for students..

Question

A theater is presenting a program on drinking and driving for students and their parents or other responsible adults. The proceeds will be donated to a local alcohol information center. Admission is $4.00 for adults and $2.00 for students. However, this situation has two constraints: the theater can hold no more than 210 people and for every two adults, there must be at least one student. How many adults can students should attend to raise the maximum amount of money?

Answer 1

The theater's maximum capacity is 210 people, so no more than 210 tickets can be sold.

Adult tickets ($4 each) will bring in more money than student tickets ($2 each), and it says that for every 2 adult tickets sold, there must be at least one student ticket sold. So, we are going to maximize the amount of money raised by selling only 1 student ticket for every 2 adult tickets sold.

Now, divide the maximum amount of people (210) by 3 (1 student ticket + 2 adult tickets = 3).

210 ÷ 3 = 70

So, we will sell 70 student tickets and then 140 adult tickets (70 x 2).

70($2) + 140($4) = $140 + $560 = $700