Evan F. answered 11/04/19
B.S. in Mathematics and M.S.Ed. with 10+ Years of Teaching Experience
The goal is to solve for y in terms of x and establishing a real and imaginary. First you must get all imaginary values on the same side of the equation,
5i-6x=(10y)i+2
+ 6x
5i = 10yi + 2 + 6x
-10yi -10yi Subtract 10i on both sides
5i -10yi = 6x + 2 Now Factor out 5i
5i(1-2y) = 6x+2 Divide 5i on both sides
5i 5i
1-2y = 6x+2 * 5i Rationalize the denominator by multiplying 5i/5i
5i 5i
1-2y = 30xi+10i Subtract 1 on both sides
-25
-1 -1
-2y = 30xi+10i -1 FInd LCD which is -25
-25
-1 * -2y = 30xi + 10i + 25 *-1
2 -25 2 Multiply by negative one half on both sides
y= 30xi + 10i + 25 Factor out 5 from the numerator
50
y= 5(6xi + 2i + 5) Simplify
50
y= 6xi + 2i + 5 factor out 2i for imaginary part
10
y= 2i(x + 1) + 5 Simplify
10
y= (x+1)i + 1 Done
5 2