Philip P. answered 11/03/19
Affordable, Experienced, and Patient Algebra Tutor
log4x = (log4x2)2
Now log4x2 = 2log4x
log4x = (2 log4x)2
log4x = 4(log4x)2
Now substitute u = log4x:
u = 4u2
0 = 4u2 - u
0 = u(4u-1)
u = 0 and u = 1/4
Substitute back log4x = u:
log4x = 0 This is undefined since 0 is outside of the domain of log4x. Let's try the other solution:
log4x = 1/4
x = 41/4 = (41/2)1/2 = 21/2 = √2
Philip P.
It's (2 log x^2)^2. There is a log property that says that log a^b = b log a for any base log. So, log x^2 = 2 log x. To solve log problems, you need to familiarize yourself with the log properties and identities.11/04/19
Ada L.
How does (2log_4 x)^2 become 4(log_4 x)^2?11/03/19