Mark M. answered 01/24/15
Tutor
New to Wyzant
I am assuming that you mean f(x) = 2x2 + 12x + 13.
The "vertex form" of a quadratic function is f(x) = a(x - h)2 + k. The graph of f is a parabola with vertex (h, k). If a > 0, then (h, K) is the lowest point of the graph and if a < 0, then (h, k) is the highest point of the graph.
f(x) = 2(x2 + 6x) + 13
To complete the square, take half of the coefficient of x and square that number. So, in this particular example, we have
[(1/2)(6)]2 = 9. Then add and subtract 9 inside the parentheses.
f(x) = 2(x2 + 6x + 9 - 9) + 13
f(x) = 2(x + 3)2 - 18 + 13
f(x) = 2(x + 3)2 - 5
f(x) = 2(x - (-3))2 + (-5). So, h = -3 and k = -5.
(h, k) = (-3, -5) is the lowest point on the graph.