Megan A. answered 10/28/19
Science and Math Tutor
a. So for the three equations, use x as your number of nickels, y as your number of dimes, and z as your number of quarters.
- .05x + .10y + .25z = 3.00
- x + y + z = 24
- y + z = x or -x + y + z = 0
b. Now let's pick a variable that would be easy to eliminate. x looks easy. If you add the bottom two equations together, you get 2y + 2z = 24. If you multiply the top equation by -20, you can then add the top two equations together. -1y + -4z = -36. Now with these two new equations, you can solve for z by eliminating y.
2y + 2z = 24
2(-1y + -4z = -36).
-6z = -48
z = 8
Plug z back into one of your equations now, 2y + 2(8) = 24, and solve for y.
y = 4
Now plug y and z into one of your original equations and solve for x.
x + y + z = 24
x + 4 + 8 = 24
x = 12
So z=8, y=4, and x=12. Larry has 8 nickels, 4 dimes, and 12 quarters.