Find all zeros....

Question

*please show me all steps that lead to the answer*

f(x)= x^3 - 3x^2 + 28x - 26

Answer 1

p={+-1,+-2, +-13,+-26}

q={+-1}

p/q = p is the set of POSSIBLE rational solutions

x=1 is a solution since 1 - 3 + 28 - 26 = 0

1 | 1 -3 28 -26

1 -2 26

_______________

1 -2 26 0

x^2 - 2x + 26 = 0

x =[ 2 +or- sqrt( 4 - 4(26))] / 2

= [2 +or- sqrt( -100)]/2

= (2 +or- 10i)/2

1 +or- 5i