The length of a rectangle is six times it’s width. If the area of the rectangle is 216 yd^2 , find its perimeter

Answer 1

Lets let the width of the rectangle (W) be x. Then the length will be equal to 6x. Then we can write area and perimeter in terms of x:

A=L*W = 6x*x = 6x²

P=2L+2W = 2(6x)+2*(x) = 14x

Using what we know for the area, we can solve the first equation for x

A = 216 = 6x²

Therefore x = 6

Now substitute the value for x into the perimeter equation to get your answer:

P = 14x = 14*6 = 84yds

Answer 2

w represents the width

6w represents the length

(6w)(w) = 216

6w² = 216

w² = 36

w = 6