Lilla H. answered 10/22/19
Very Patient Finite Math Tutor with 20+ Years of Teaching
Mesa,
1.
Let's put the letter "i" down to the first spot, so we have 8 more spots to fill out with the letters: 1c, 1o, 2m, 2t, and 2e. This is permutation with repetitions, so the answer is 8!/(2!2!2!) = 5040.
Another way to thin about is that you choose 1 spot for a "c" : C(8,1), then 7 spot remains
Then you choose one spot for "o": C(7,1), then the 2 m's: C(6,2), the 2 t's: C(4,2) and the e's: C(2,2)
This gives you C(8,1)*C(7,1)*C(6,2)*C(4,2) *C(2,2) = 5040 different ways
2.
We have 2 options, whether we choose the 2 o's or not. If we do:
Let's find 2 spots for the 2 o': C(4,2) ways, the next spot we have 3 choices( b, k or s): C(3,1), and for the last spot 2 choices left: C(2,1)
If we don't have 2 o's: we have 4*3*2*1 choices (4 choices for the first spot, 3 for the next etc.
We have to add the 2 options:
C(4,2)*C(3,1)*C(2,1) + 4*3*2*1 =36 + 24 =60 different ways.
Let me know if you have more questions.
Mesa H.
Thank you for the help!10/25/19