
Suzanne O. answered 10/21/19
International Experience and Multiple State Certifications
Let's start with what we know:
area of a trapezoid = (base1 plus base2) divided by 2 times height or a = (b1 + b2) / 2 * h
base1 = height (h) + 6
base2 = height (h) + 2
a = 32 square meters
So now we start replacing values with givens in order to solve the equation for height, our only unknown.
a = (b1 + b2) / 2 * h
32 = (h+6+h+2) / 2 * h
32 = (2h + 8)/2 * h
32 = (h + 4) * h
32 = h squared + 4h
h = 4 meters
base 1 = 4 + 6 = 10 meters
base2 = 4 + 2 = 6 meters
I wrote the solution for h in bold italics because I solved (32 = h squared + 4h) by thinking about the numbers themselves. This means I assume that we are working with positive whole numbers. There are only 5 possible values for h {1, 2, 3, 4, 5}, zero won't help us. I stopped my list at 5 because 5 * 5 + 4 * 5 is 25 + 20 = 40 (too big). The next logical value to test is 4, which works: 4 * 4 + 4 * 4 = 16 + 16 = 32 (just right).
double check when h = 4:
32 = (10+6) / 2 * 4
32 = 16 / 2 * 4
32 = 8 * 4
32 = 32 👍
HOWEVER, if we want to play by the rules, there are 2 possible answers to the equation:
...
32 = h squared + 4h
0 = h squared + 4h - 32 Quadratic 😯
0 = (h + 8)(h - 4)
h = 4, h = -8
double check where h = -8:
base 1 = -8 + 6 = -2 meters
base2 = -8 + 2 = -6 meters
32 = (-2 + -6) / 2 * -8
32 = -8 / 2 * -8
32 = -4 * -8
32 = 32 👍
You CAN have a negative measurement, it just puts the figure in a different quadrant on an x-y plot. Of course, we don't usually model the real world in negative measurements.
Now you will have to decide based on what you are learning in class. Will you use the simple h=4 version, or the correct h= -8, h=4?

CRUZ C.
I agree that there can be negative solutions to math problems; however to suggest that my height is negative 72 inches or that my weight is negative 150 pounds would be inconsistent with generally accepted standards of reality. What is your goal to help or to confuse?10/21/19