Writing the equation of a secant line

Question

Given h(x) = x^3 +1

find the equation of a secant line passing through (-3,h(-3)) and (1,h(1)). Write your answer in y = mx+b

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Answer 1

h(-3) = -26

h(1) = 2

the slope is (2 - -26)/(1 - -3) = 28/4 = 7

B = y-mx = 2 - 7*1 = 2 - 7 = -5

y = 7x -5