Find a formula for an exponential function f that satisfies f(-3) = 5/8 and f(2) = 20

Answer 1

y = C* B^x

(2,20)

20 = C * B^2

(-3,5/8)

5/8 = C/B^3

5b^3 = 8C

(5/8)b^3 = C

20 = (5/8)b^3 * b^2

20 = (5/8) b^5

32 = b^5

b = 2 ---> C = 5

So the exponential function is

y = 5 * 2^x