
Arturo O. answered 10/11/19
Experienced Physics Teacher for Physics Tutoring
r1 = the zero with a multiplicity of 3
r2 = the zero with a multiplicity of 2
p(x) = A(x - r1)3 (x - r2)2
where A ≠ 0.
Rachel B.
asked 10/09/19Arturo O. answered 10/11/19
Experienced Physics Teacher for Physics Tutoring
r1 = the zero with a multiplicity of 3
r2 = the zero with a multiplicity of 2
p(x) = A(x - r1)3 (x - r2)2
where A ≠ 0.
David L. answered 10/09/19
Ph.D. Chemist tutoring math and science
Consider that a polynomial with five zeros (a, b, c, d, e) can be expressed as
0= (x-a)(x-b)(x-c)(x-d)(x-e)
To solve the problem, let a, b, and c be one value (zero would be easy) and let d and e be a second value (1 would be easy). Plugging in and multiplying gives
0 = x^5 -2x^4 + x^3
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