P= k/A
4 = k/40
k = 160
Grace G.
asked 10/08/19The pressure, P (in lbs/in^2), that a 160-pound person's shoe exerts on the ground when walking varies inversely with the area, A ( in in^2), of the sole of the shoe. When the shoes have a sole area of 40in^2, the pressure is 4lb/in^2. Find an equation that relates these variables.
P= k/A
4 = k/40
k = 160
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