Line L passes through point (12,0) and p is the graph of 6x-57=6. If L is perpendicular to p, what is the equation of L?

Answer 1

The slope of a perpendicular line is the negative reciprocal of the original line. I am going to take a guess and say that you meant type 6 x - 5 y = 6 instead. Solve this for y as follows:

-5y = -6x - 6 moved x term to right

y = 6/5 x + 6/5 divided every term by -5

Therefore the slope of this line is 6/5. A line perpendicular to this line will have a slope of m= -5/6. Using the point of (12,0), we plug these into the point slope formula y - y₁ = m ( x - x₁) m = -5/6 x₁ = 12 y₁ = 0

y - 0 = -5/6 (x - 12)

y = -5/6 x + 10