Kevin E. answered 10/02/19
Tutor
New to Wyzant
A chemist going back to school for cyber security.
If |x-1|+2 is in the denominator, than all real number which would make |x-1|+2≠0. If it's just |x-1| in the denominator (how it should be read as written), then all real numbers which make |x-1|≠0.