Find the equation for the line passing through the point (−2,4) and parallel to the line whose equation is y=3x+10

Answer 1

the slope of the given line is 3.

The parallel line must also have slope 3.

It eats (-2,4) , so

B = y - mx

= 4 - (3)(-2)

= 4 - (-6)

= 10

y = 3x + 10