college algebra

Question

You invested ​$ 25,000 in two accounts paying 6% and 9 % annual​ interest, respectively.

If the total interest earned for the year was

$ 1620 how much was invested at each​ rate?

Answer 1

25000 = x + y

0.06x + 0.09y = 1620

6x + 9y = 162000

6x + 9* (25000 - x) = 162000

6x + 225000 - 9x = 162000

-3x + 225000 = 162000

-3x = -63000

x = 21000

y = 4000