write the equation of the line with a slope of 3/4 and y-intercept of -7

Question

in slope-intercept and point-slope form

Answer 1

y=mx+b m=slope b=y-intercept. With m=3/4 and b=-7 the equation is

y=3x/4-7 or to remove fractions, multiply by 4 to get 4y=3x-28

point slope requires a point. If you know the y-intercept of -7 that's the same as the point (0,-7)

(y+7)/(x-0)=m=3/4 rise over run = slope

y+7=3x/4 or multiply through by 4 to get 4y+28=3x

in either case, sometimes the preferred final equation is of the ax+by=a constant form

or 3x-4y=28 or some instructors like it all on the left side like 3x-4y-28=0

Answer 2

The equation for a line is y = mx + b, where m is the slope and b is the y intercept. In this problem you are told that the slope, or m, is 3/4, and the y-intercept, or b, is -7. Therefore, we can stat the equation of the line as

y = 3/4x - 7.