PLEASE HELP I AM SO CLOSE

Question

A Web music store offers two versions of a popular song. The size of the standard version is
2.8
megabytes (MB). The size of the high-quality version is
4.6
MB. Yesterday, there were
580
downloads of the song, for a total download size of
2002
MB. How many downloads of the high-quality version were there?

Answer 1

Hello Gibran,

 

Lets say the number of standard version downloads is S and the number of High-Quality version downloads is H.

 

Since the total number of downloads was 580, then S+H=580 

 

If 2002 MB was used in total than our equation would be:

 

2.8*S+4.6*H=2002.

 

We will have to find out what S, or what H, is equal too. Since the question is for High Quality versions, we will use H.

 

From this equation (S+H=580) so S=580-H

 

So we can go back to this equation (2.8*S+4.6*H=2002) and substitute S for 580-H because S=580-H

 

We end up with 2.8*(580-H)+4.6*H=2002.

 

From here you can solve for H. And the H would be your answer. 

 

 

Good Luck,

Ayodeji A.

Answer 2

Let x = the number of HQ downloads.  Since there were 580 total downloads, the number of standard downloads is 580-x.

 

2002 mb = (580-x)*(2.8 mb) + (x)*(4.6 mb)

 

2002 = 1624 - 2.8x + 4.6x

 

Solve for x.