How many ml of 2.50 M NaOH are needed to react with 0.289 of o-toluic acid?

Question

Answer 1

The mole ratio of NaOH to o-toluic acid is 1 : 1 as seen in the balanced equation. The following is the answer to the question in the header, not the answer to the question in the attachment.

0.289 mol o-toluic acid x 1 mol NaOH/mol acid = 0.289 mol NaOH

(x L)(2.50mol/L) = 0.289 mol

x = 0.1156 L = 115.6 mls = 116 mls (to 3 significant figures)