p(x)+=x^3+2x^2+4

Question

Quotient=

Remainder=

p(-2)=

Answer 1

p(x) = x^3 + 2x^2 + 4

p(-2) = (-2)^3 +2(-2)^2 + 4 = -8 +4+4 = 0

p(-2) = 0

-2 is a zero, root, solution or x intercept if you graph the equation. It is the only x intercept, y intercept=4

x=-2

x+2 = 0, x+2 is a factor

divide x+2 into x^3 +2x^2 + 4, the quotient = x^2

remainder = 4

x^2 times x+2 = x^3 + 2x

x+2 divided into x^3+2x^2 +4 = x^2 + 4/(x+2)