if t1 equals 78 and s equals 48 what is the common ratio of the infinite geometric series?

Answer 1

If t₁ = first term and S = sum of entire series, then S = t₁ / (1 - r), where r is the common ratio.

So, we have 78 / (1 - r) = 48

78 = 48 - 48r

48r = 30

r = 30/48 = 5/8