
Al P. answered 09/19/19
Online Mathematics tutor
E = IZ
You are given I and E, so they want you to solve for Z. To do that, divide both sides by I (so Z will be alone on the right):
E/I = Z
This can be written more conveniently:
Z = E/I
Substituting in the values given for E and I:
Z = (1+9i)/(4+3i)
Multiply the right hand side by (4-3i)/(4-3i) (which =1 so we're not changing anything):
Z = (1+9i)/(4+3i) * (4-3i)/(4-3i)
Z = ((1+9i)(4-3i)) / ((4+3i)(4-3i))
Simplify:
Z = (4-3i+36i-27i2 ) / (16+12i-12i-9i2)
Z = (31+33i) / 25
[ Notice how you can always make the denominator a real number by multiplying by the complex conjugate: (a+bi)(a-bi) = a2 -abi + abi - b2i2 = a2+b2 , making use of i2 = -1. ]