The length of a new rectangular playing field is 77 yards longer than double the width. If the perimeter of the rectangular playing field is 374 yards, what are its​ dimensions?

Answer 1

I recommend setting problems like this up algebraically first because it is easier to visualize. Let's first define width and length in terms of W and L.

W = width

L = length

We have a set of equations. The first is the comparison listed in the first sentence and the second is the perimeter.

2*W + 77 = L

2*W + 2*L = 374

Now you can simply plug in 2*W + 77 for L in the second equation.

2*W + 2 (2*W + 77) = 374

2W + 4W + 154 = 374

6W = 220

W = 36.667

Now we can solve for L

2*36.667 + 77 = 150.333

L = 150.333