Geomatics and surveying

Question

The dimensions of a rectangle shaped lot measured with a 100m tape is 135.175m and 67.432m. A standardization exercise revealed that the tape was actually short by 7.9cm.

Determine the tru perimeter of the lot and the true area

Answer 1

Measured rectangle side lengths: 135.175m and 67.432m.

The measuring tape used was 7.9 cm short = 0.079m. Therefore correct lengths of the rectangle sides are the measured plus the 0.079m shortness: 35.175m + 0.079m = 35.254 and 67.432m + 0.079m = 67.511 m.

Answer 2

The perimeter (u) of a rectangle defined as u=2(a +b), where "a" and "b" are the two respective lengths.A tape length of 100 meter is 10,000 cm in length. The tape in question is 7.9 cm short which equals 99.921 percent of what the 100 meter tape should be. Multiplying both "a" and "b" by 99.921 percent and then solving for "u" will give you the actual perimeter.