find f(2x) for the function f(x)=2x^3-3x^2-x+4. Explain the transformation that f(2x) applies to the f(x) function.

Answer 1

The transformation is a vertical stretch - or it could be called a horizontal compression.

Answer 2

simply substitute 2x in for every occasion of x

 f(2x)=2(2x)^3-3(2x)^2-2x+4

handle your powers first

2(8x^3) - 3(4x^2) -2x +4

now distribute your coefficiants

16x^3 -12x^2 -2x+4