L=4W
2(L+W)=62 => L+W=31
4W + W = 31
W=6.2
L=24.8
Andy M.
asked 09/15/19The length of a rectangle is 1 more than 4 times its width. If the perimeter of the rectangle is 62 meters, find the dimensions of the rectangle.
L=4W
2(L+W)=62 => L+W=31
4W + W = 31
W=6.2
L=24.8
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