The sum of 3 consecutive integers is 33 more than the least

Question

I want to find the integers

Answer 1

3x = 33 + x-1,

x-1 =smallest integer, x next bigger, x+1 the largest of 3 consecutive integers

2x = 32

x = 16

15,16 & 17 are the 3 consecutive integers where the sum = 33 more than the smallest

3(16) = 33+15

48 = 48