Mark M. answered 09/11/19
Retired college math professor. Extensive tutoring experience.
S = 2πr(h + r)
S = 2πrh + 2πr2
2πrh = S - 2πr2
h = (S - 2πr2) / (2πr)
Alex A.
asked 09/11/19S= 2πr(h+r) solve for h
Mark M. answered 09/11/19
Retired college math professor. Extensive tutoring experience.
S = 2πr(h + r)
S = 2πrh + 2πr2
2πrh = S - 2πr2
h = (S - 2πr2) / (2πr)
Whiz S. answered 09/11/19
Experienced and patient Math tutor
S= 2πr(h+r) solve for h
S = 2πr(h+r)
divide by 2πr to both sides
S / 2πr = h+r
subtract r from both sides
S / 2πr - r = h
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