Lilla H. answered 09/10/19
Very Patient Finite Math Tutor with 20+ Years of Teaching
Solution1:
So let's select Sally, because she must be selected. We now have a pool of 5 males and 5 females, from which we need 4 males and 3 females (Sally is already selected). This can be done in C(5,4)*C5,3)= 5*10=50 different ways.
50 different options will include Sally.
Solution#2
There are a total of C(5,4)*C6,4)= 5* 15= 75 ways to select 4 men and 4 women.
The number of ways we do not select Sally : C(5,4)*C(5,4)= 5*5 = 25
Therefore the number of ways we select Sally in this case is 75 - 25 = 50 (Same answer as in option1