Let’s make a right triangle with its legs on the x-axis and y-axis and the vertex at (0,0). The area of a triangle is A=1/2bh. We know this area is 2 square units. So we can use (0,2) and (2,0) points as the other end points of the legs of the triangle(which are also the y and x intercepts). These two points and the vertex give us the length of b= 2-0=0 and h=2-0=0. Now we can find the slope of the parent linear function
m=y2-y1/x2-x1=2-0/0-2=-1
let’s write the parent linear function using one of our points
y-k=m(x-h)
y-0=-1(x-2)
y=-x+2
To be able to move the parent function vertically up we must add a number k to this equation and our translated function is
y=(x+2)+k
