y = 0.9t+2 = 0.9t · 0.92 = (0.81)·(0.9)t = (0.81)(1-0.1)t where a = 0.81 and r = 0.1. This is exponential decay since 0.9 < 1.
Michael S.
asked 09/06/19Exponential growth and Decay question
Rewrite $y=0.9^{t\ +\ 2}$y=0.9t + 2 in the form $y=a(1+r)^t$y=a(1+r)t or $y=a(1-r)^t$y=a(1−r)t . Then tell whether the model represents exponential growth or exponential decay.
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