(-6+5i)(-3+2i) in complex number

Answer 1

(-6+5i)(-3+2i)

This can be FOILED

F - First (-6)(-3) = 18

O - Outer (-6)(2i) = -12i

I - Inner (5i)(-3) = -15i

L - Last (5i)(2i) = 10i² Since i²= -1, this would simplify to (10)(-1) = -10

18-12i-15i-10 Combine like terms

8-27i