write an equation of the line in standard form that passes throigh the points (2,-3) and (-1,-4)

Answer 1

Slope= (y2-y1)/(x2-x1)= (-4+3)/(-1-2)= 1/3

Wkt, eqn of a line is y=mx+c so both the points must satisfy this equation.

-3=(1/3)(2)+c

Solve for c, c= -11/3.

So, equation of the line is

y= (1/3)x-11/3

3y= x-11