Any point on the y-axis can be expressed as (0,y).
So, the distance from (5,-3) to (0,y) is 13.
√[(0-5)2 + (y+3)2] = 13
y2 + 6y + 34 = 169
y2 + 6y - 135 = 0
(y + 15)(y - 9) = 0
y = 9 or y = -15
The points are (0,9) and (0,-15)
Any point on the y-axis can be expressed as (0,y).
So, the distance from (5,-3) to (0,y) is 13.
√[(0-5)2 + (y+3)2] = 13
y2 + 6y + 34 = 169
y2 + 6y - 135 = 0
(y + 15)(y - 9) = 0
y = 9 or y = -15
The points are (0,9) and (0,-15)
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