If the sum of five consecutive even integers is 140, what is the smallest of the five integers?

Answer 1

Let X, X+1, X+2, X+3, and X+4 be the 5 consecutive integers.

Given: X + X+1 + X+2 + X+3 + X+4 = 140

This simplifies to 5X + 10 = 140

Subtract 10 from both sides: 5X + 10 - 10 = 140 - 10 to get 5X = 130

Divide both sides by 5 to get X, the smallest of the 5 consecutive numbers: 5X/5 = 130/5

X = 26

Check: 26+27+28+29+30 = 140