Hailey B.
asked 08/27/19We want to choose 5 letters without replacement from 15 distinct letters
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1 Expert Answer
Arthur D. answered 08/27/19
Tutor
4.9
(388)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
are you asking how many ways to do this ??
if so, use n!/r!(n-r)! where n=15 and r=5
15!/5!(10)!=
(15*14*13*12*11)/(5*4*3*2*1)=
simplify....
7*13*3*11=
3003
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Inactive Tutor
From what you present, there are no restrictions.08/27/19