Write an equation, in standard form, of the line that passes through the point (-2, 8) and is perpendicular to a line with a slope of 1.5

Answer 1

Write an equation, in standard form, of the line that passes through the point (-2, 8) and is perpendicular to a line with a slope of 1.5

=>

perpendicular to a line with a slope of 1.5

1.5 =3/2

so slope of line = -1/ 1.5= -1/ 3/2 = -2/3

line that passes through the point (-2, 8)

first we will write equation in point slope form

y-y1 =m(x-x1)

y-8=-2/3(x+2)

3y-24=-2(x+2)

3y-24 =-2x-4

2x+3y-20 =0 ---------------equation in standard form

Answer 2

THe slope of the given line is 1.5 = 3/2

THe slope of the perpendicular line is -2/3, and it eats (-2,8)

B = y - mx = 8 - (-2/3)(-2)

= 8 - 4/3

= 24/3 - 4/3 = 20/3

y = -(2/3)x + 20/3 <--- this is the slope -intercept form.

multiplies everything by 3:

3y = -2x + 20

2x + 3y = 20