The length of a rectangle is 10 meters more than its width. If the perimeter of the rectangle is 80 meters, find the dimensions of the rectangle

Answer 1

The formula for the perimeter of a rectangle is:

2w + 2L = P Where w is width and l is length

now this problem tells us that the length is 10 meters more than it’s width. So:

L = 10 + w

We can substitute L with 10 + w in our perimeter equation and also substitute 80 in for P which is our perimeter and then solve:

2W + 2(10 + W) = 80

2W + 20 + 2W = 80

4W + 20 = 80

-20. -20

4W = 60

/4 /4

W = 15 meters

since we know the length is 10 meters longer than our width we can just add 10 to find the length:

L = 15 + 10 = 25 meters

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Answer 2

Perimeter = 2 * Length + 2 * Width

P = 2L + 2w

Length = width + 10 ----> L = w+10

P = 2*(w+10) + 2w

80 = 2w + 20 + 2w

80 = 4w + 20

60 = 4w

w = 15

Length = 25 width = 15