Factor the polynomial expression 3x^2+2.

Answer 1

If we allow complex roots, then the polynomial can be factored as follows:

3x² + 2 = 0

x² = -2/3

x = ±√(2/3) i

3x² + 2 = 3(x² + 2/3) = 3(x - √(2/3) i)(x + √(2/3) i)

Answer 2

The only possibilities are:

(3x+1)(x+2)

(3x+2)(x+1)

(3x-1)(x-2)

(3x-2)(x-1)

These don't give a middle term of 0. So this cannot be factored, it is PRIME.