An even integer is divisible by 2; therefore, 2n is even.
2n + 2m = 2(n+m)
2n+1 and 2m+1 are 2 odd integers
2n+1+2m+1= 2n+2m+2=2(n+m+1)...the sum of two odd integers is even.
Alex H.
asked 08/16/19An even integer is divisible by 2; therefore, 2n is even.
2n + 2m = 2(n+m)
2n+1 and 2m+1 are 2 odd integers
2n+1+2m+1= 2n+2m+2=2(n+m+1)...the sum of two odd integers is even.
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