Arthur D. answered 08/16/19
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
let ab and ba be the numbers
10a+b+10b+a=65
11a+11b=65
11(a+b)=65
65 is not divisible by 11 so a+b cannot be an integer
10a+b+10b+a=154
11a+11b=154
11(a+b)=154
a+b=154/11
a+b=14
a=5, b=9 gives 59 and 95, 59+95=154
a=6, b=8 gives 68 and 86, 68+86=154
a=7, b=7 gives 77 and 77, 77+77=154