
Victoria V. answered 08/15/19
20+ years teaching Algebra 2 subjects & beyond.
We need a variable for the larger (L) and for the smaller (S).
"Five times the larger" becomes 5L
"is" becomes =
"eleven more than" becomes ____ + 11
"three times the smaller number" becomes 3S
Putting the first sentence all together, it becomes
5L = 3S + 11
"Three times the smaller is" becomes 3S =
"sixteen less than" becomes _______ - 16
"four times the larger" becomes 4L
Putting the second sentence all together, it becomes
3S = 4L - 16
Now we have a system of equtions with two unknowns, L and S. We want all of the variables on one side and all of the constants on the other, so these two equations rearrange into
5L - 3S = 11
-4L + 3S = -16
Adding vertically, the S terms cancel and we are left with
L = -5
Plug that back into 3S = 4L-16 and find 3S = 4(-5) - 16 = -36
3S = -36, so S = -12
Final answer:
Larger number is -5
Smaller number is -12