Dick S. answered 08/07/19
Science Tech Eng Math Physics, Simple Explanations, UC Berkeley Grad
1) x = (-b ± √(b2-4ac))2a
are the two solutions to the quadratic equation:
2) ax2+bx+c=0
when a, b, and c are known, two solutions are found by using eqn 1) one using a + sign and one using a - sign where you see the ± sign.
There is another way of looking at this. If we consider the graph of:
3) y = ax2+bx+c
This is the general equation for a parabola, which either crosses the x-axis twice or not at all.
Picture the graph of a parabola, it can concave up (smiling), or concave down (frowning), and it can be drawn completely above or below the x-axis, or it can be drawn crossing the x-axis in two places. These are the only choices. Go ahead and draw some freehand on graph paper right now to see what I mean.
Now,
If:
(b2-4ac) > 0
then the square root in eqn 1) is real and the two solutions from eqn 1) yield the x-intercepts of the parabola, that is where the parabola crosses the x-axis, which will be in two places.
If:
(b2-4ac) < 0
then the square root in eqn 1) is complex and the equation has no real roots, thus, in this case, the parabola does not cross the x-axis, its graph is either entirely above or below the x-axis.