Bam K. answered 01/15/15
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d2y/dx2 + 9y = 0 ; dy/dx = Acos(Ax) ; d2y/dx2 = -A2 sin(Ax)
-A2 sin(Ax) + 9 sin(Ax) = 0 <----> (9 - A2) sin(Ax) = 0
(3 - A)(3 + A) sin(Ax) = 0
The values of A that make y = sin(Ax) a solution to the differential equation are 3, -3, and 0