John C.

# Calc 2 For Engineers Problem in Description

Find the area of the region bounded by the graphs of y=7tanx and y=7secx on the interval [0, pi/4].

I would really appreciate any help with this problem! Thank you so much.

Yohan C.

Which Axis of revolution?
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09/21/14

Chen Jang T.

This is an area problem, not volume of revolution
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09/21/14

John C.

It does not supply an axis of rotation.
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09/21/14

## 3 Answers By Expert Tutors

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John C.

This seemed correct to me, but it is not the right answer. Any other suggestions?
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09/22/14

SURENDRA K.

Hello John,
By-
Francisco
Yohan
Myself
Which one you say is wrong???
I can assure you, the answer given by me is correct.

Surendra
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09/22/14

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Math Tutor (up to Calculus) (not Statistics and Finite)

Yohan C.

First equation is for revolution on x-axis and y-axis for second one.
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09/21/14

Yohan C.

If that is the case, you integrate ∫[7 (sec x) - 7 (tan x)] dx with upper limit pi/4 and lower limit 0.

You will get, 7 [ln |sec x + tan x| - ln |cos x|].  As you put 0, you will get 0 because ln 1 is 0.  As you put pi/4, you will get, 7 [ln  |√ 2+ 1| - ln |√ 2/2|].

Maybe this is what you looking for.  Sorry for misunderstanding.
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09/21/14

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