Write equation for the line in point slope form

Question

Passing through (5,-3) and perpendicular to the line whose equation is y=1/3x+1

Answer 1

The slope of the perpendicular line is the negative reciprocal. If m=1/3, the perpendicular slope is -3 We plug this and the point given into the following equation

(y-y₁)=m(x-x₁)

(y-(-3))=-3(x-5) Simplify and use the distributive property

y+3 = -3x+15 Subtract 3 from both sides

y+3-3 = -3x+15-3

y=-3x+12