a + b = 6000
0.04a = 0.06b
First, let's solve the 1st equation for either a or b. I'm gonna do a.
a = 6000 - b
Now, substitute!
0.04(6000 - b) = 0.06b
240 - 0.04b = 0.06b
240 = 0.1b
b = $2400
a = 6000 - 2400
a = $3600
RISHI S.
asked 07/20/19Erik Borrows a total of $6000 in two separate loans for one-year period. At the end of one year, he pays back the entire amount of each loan plus simple annual interest at the rate of 4 percent for the first loan and 6 percent for the second loan. If the interest paid on each loan is same amount, how much total interest did Erik pay on these two loans
a + b = 6000
0.04a = 0.06b
First, let's solve the 1st equation for either a or b. I'm gonna do a.
a = 6000 - b
Now, substitute!
0.04(6000 - b) = 0.06b
240 - 0.04b = 0.06b
240 = 0.1b
b = $2400
a = 6000 - 2400
a = $3600
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.