Right triangles.

tanα=sinα/cosα=(a/c)/(b/c)=a/b

tanβ=sinβ/cosβ=(b/c)/(a/c)=b/a

Alyssa R.

asked • 07/18/19What are some of the ways **tanθ=sinθ/cosθ** can be expressed?

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Right triangles.

tanα=sinα/cosα=(a/c)/(b/c)=a/b

tanβ=sinβ/cosβ=(b/c)/(a/c)=b/a

I believe the question is simply asking you to re-arrange that equation to get 2 different ones.

Basically solve for **sin(θ) **and **cos(θ)**.

What is **sin(θ) **equal to in terms of **cos(θ) **& **tan(θ)**?

What is **cos(θ) **equal to in terms of **sin(θ) **& **tan(θ)**?

Hint: One of those two is a fraction, while the other is a product.

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