Hello, thank you for taking the time to post your question!
The key on this type of question is to use the information given in order to set up an algebraic expression.
On this one we have
x + y = 32 because the numbers add up to be 32
x = 3y + 8 because one number is 8 more than 3 times the other
from there I would plug in the second equation into the first one in order to solve for the value of “y”
3y + 8 + y = 32
4y = 24
y = 6, meaning that
x = 3(6) + 8 = 18 + 8 = 26
so the two numbers that meet this criteria are 6 and 26
I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)
